What is the mass of #6.02 * 10^23# atoms of calcium?

1 Answer
anor277
Jun 25, 2016

In #1# #mol# of #Ca# #"atoms"#, there are #N_A# individual calcium atoms.

Explanation:

How does this help you? Well, it happens that #N_A#, #"Avogadro's Number"# #~=# #6.022xx10^23*mol^-1#.

And it is stated on your trusty Periodic Table that the molar mass of #Ca# is #40.08*g*mol^-1#. So, if we specify a molar quantity, we specify a precise number of atoms and molecules that can be approximated by mass.

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