What is the mass of #6.2 * 10^20# molecules of carbon monoxide?

1 Answer
Mar 26, 2016

First find how many moles are present by comparing with Avogadro's Number: #n=(6.2xx10^20)/(6.02xx10^23)=0.001# #mol#

The molar mass is #12+16=28# #gmol^-1#.

To find the mass, #m=nM=0.001xx28=0.028# #g#.