# What is the mass of 7.83 * 10^23 atoms Cl?

Here we have a number that is in excess of Avogadro's number, $6.022 \times {10}^{23}$ $=$ ${N}_{A}$.
Since I know that if I have $6.022 \times {10}^{23}$ atoms of chlorine I have a mass of $35.45$ $g$ of chlorine, then all I have to do is give the product, $35.45 \cdot g$ $\times \frac{7.83 \times {10}^{23}}{6.022 \times {10}^{23}}$ $=$ ?? $g$.