What is the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium?

1 Answer
Mar 14, 2016

Answer:

Approx. #1.5# #g#. We work out the molar quantities, in that we know the mass of Avogadro's number of metal atoms. (How do we know this?)

Explanation:

We want the same number of each metal atom; therefore, we require an equality in the number of moles of cadmium and aluminum.

#"Moles of cadmium"# #=# #(6.35*g)/(112.41*g*mol^-1)# #=# #??mol#

#"Mass of aluminum"# #=# #(6.35*g)/(112.41*g*mol^-1)# #xx# #26.98*g*mol^-1# #=# #??g#

In each case I have used the concept of the mole. Avogadro's number (1 mole) of each metal atom has a specific mass; and these masses are tabulated on the Periodic Table.