# What is the mass % of H in C9H10N2?

Sep 15, 2017

The mass % of $\text{H}$ in $\text{C"_9"H"_10"N"_2}$ is $\text{6.895%}$.

#### Explanation:

The molecular formula $\text{C"_9"H"_10"N"_2}$, indicates that in one mole of the compound, there are 9 moles of carbon atoms, 10 moles of hydrogen atoms, and 2 moles of nitrogen atoms.

To calculate the mass % of H atoms in $\text{C"_9"H"_10"N"_2}$, divide the molar mass of H atoms by the molar mass of the compound and multiply by 100.

Mass of $\text{C"_9"H"_10"N"_2} :$$\text{146.193 g/mol}$ https://www.ncbi.nlm.nih.gov/pccompound?term=C9H10N2

Mass of $\text{H}$ atoms: (10xx1.008" g/mol")="10.08 g/mol"

Divide and multiply by 100:

(10.08color(red)cancel(color(black)("g")))/(146.193color(red)cancel(color(black)("g")))xx100="6.895% H"