# What is the mass of one atom of copper in grams?

$1$ atom of $\text{Cu}$ has a mass of $1.055 \times {10}^{- 22}$ $\text{g}$.
"1 atom Cu" * ("1 mol Cu")/(6.022xx10^23 "atoms Cu") * "63.546 g Cu"/"1 mol Cu"= 1.055xx10^(-22) $\text{g Cu}$
Avogadro's Number $\left(\text{1 mole" = 6.022xx10^23"particles}\right)$ and the relative atomic mass of copper $\left(\text{1 mole of copper = 63.546 g}\right)$ are the equalities required to make this conversion.