# What is the mass of one atom of magnesium in grams?

Dec 15, 2016

So $4.03594014 \cdot {10}^{-} 23 \text{grams}$

#### Explanation:

Here are some prefined values.

m = mass = $\text{g}$
M = molar mass = "g"/("mol")
A = Avagadro's Constant = (6.02214086*10^23"particles")/"mol"

$\text{mass"/"particle" = "M(Mg)"/"A}$, the particle being the one atom, so the mass for one atom.

$m \left(M g\right) = \text{M(Mg)"/"A" = (24.305"g"/"mol")/(6.02214086*10^23 "particle"/"mol") = 4.03594014 * 10^-23 "g"/"particle}$

So $4.03594014 \cdot {10}^{-} 23 \text{ grams}$ is the mass per particle, the particle being an atom.