Question

What is the mass of sodium sulfate in 675 mL of 0.025 M sodium sulfate?

Answer 1

Approx. `2.5*g`

Explanation:

We work out the moles of solute....

`n_"sodium sulfate"=675xx10^-3*Lxx0.025*mol*L^-1=0.0169*mol`

...and then the mass of solute....

`"mass"_"sodium sulfate"=0.0169*molxx142.04*g*mol^-1~=2.5*g`