What is the mass percent of carbon in propanoic acid #(C_2H_5COOH)#?

The molar mass of #C = 12.01, H = 1.0079#, and #O=16.00#.

1 Answer
Mar 27, 2016

Answer:

#%"(C in C"_2"H"_5"COOH)"= 48.64%#

Explanation:

#"A"_r "(C)"= 12.01#
#"M"_r "(C"_2"H"_5"COOH)"= 3xx12.01 + 6xx1.0079 + 2xx16.00 = 74.0774#

#%"(C in C"_2"H"_5"COOH)"= ("A"_r"(C)"xx"N"°"(C in C"_2"H"_5"COOH)")/("M"_r"(C"_2"H"_5"COOH)")xx100 = (12.01xx3)/74.0774xx100= 48.64%#