# What is the maximum value of y=-3sinx+2?

Oct 11, 2017

$5$

#### Explanation:

For: $y = - 3 \sin x + 2$

Since $\sin x$ is multiplied by a negative value, we want $\sin x$ to be a minimum value.

$0 \le x \le 2 \pi$

$- 1 \le \sin x \le 1$

Maximum value:

If $x = \frac{3 \pi}{2}$. then $\sin x = - 1$ and $- 3 \sin x + 2 = 5$

Graph:

graph{-3sinx+2 [-12.66, 12.65, -6.33, 6.33]}