What is the measure of an exterior angle in a regular heptagon?

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Answer 1 · 2018-02-25T01:39:04

#51.43^{\circ}# is the measure of each exterior angle in a regular heptagon.

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In a regular polygon,

#\text{the size of each exterior angle}\ \ =\ \ 360^{\circ} \div\ \text{number of sides}#

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In this case, the size of the exterior angle of a regular heptagon is # 51.43^{\circ}# because #360^{\circ} \div 7 = 51.43^{\circ}#

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And the interior angle must be #128.57^{\circ}# because #180^{\circ} – 51.43^{\circ} = 128.57^{\circ}#