Question

What is the middle line of the function `f(t)=pisin(pit-pi)+pi`?

Answer 1

`y = pi = 3.1416`, nearly

graph{(3.14(sin(3.14(x-1))+1)-y)(y-3.14)=0 [-20, 20, -10, 10]}

Explanation:

Period of this sine wave is `(2pi)/pi=2`.

The amplitude= `(max f - min f )/2=(2pi-0)/2=pi`

Cyclic zeniths ( crests ) lie on `y = f = (2pi)`

Cyclic nadirs ( lowest points ) lie on `y =0`.

The middle ( axial ) line is `y = pi`