What is the midpoint between #C(1, 2,3)# and #D(3,0,3)#?
1 Answer
Sep 21, 2014
The answer is
The answer can be found with the average of the components:
#M=((C_x+D_x)/2, (C_y+D_y)/2, (C_z+D_z)/2)#
#=((1+3)/2, (2+0)/2, (3+3)/2)#
#=(2,1,3)#
