What is the minimum amount of energy released in kilojoules when 450.0 grams of water vapor condenses to a liquid at 100°C?

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Answer 1 · 2016-04-13T18:26:56

Approx. #10^3# #kJ# of energy are released

#H_2O(g) rarr H_2O(l) + "energy"#

Now we need investigate only the phase change, because both #H_2O(g)# and #H_2O(l)# ARE both at #100# #""^@C#.

So, we have been given the heat of vaporization as #2300# #J*g^-1#. And, #"energy"# #=# #450.0*gxx2300*J*g^-1# #=# #??#

Because the energy is RELEASED, the calculated energy change is NEGATIVE.