Question

What is the mol solute and molarity of `KNO_3` which has the solute mass 22.5 g and volume solution 125.0 mL?

Answer 1

`[KNO_3]~=2*mol*L^-1`

Explanation:

We take the quotient `"moles of solute"/"volume of solution"`...

`=((22.5*g)/(101.1*g*mol^-1))/(125.0*mLxx10^-3*L*mL^-1)=??*mol*L^-1`...