Question

What is the mol solute and volume solution of `C_12H_22O_11` which has the solute mass 55.38 g and the molarity 0.150 mol/L?

Answer 1

We use the relationship...... there are `0.162*mol` of sucrose... and get a volume of solvent over `1*L`.

Explanation:

We use the relationship...

`"Concentration"="Moles of solute"/"Volume of solution"`

And so `"moles of solute"="concentration"xx"volume"`

`((55.38*g)/(342.3 *g*mol^-1))/("volume of solution")=0.150*mol*L^-1`

And `"volume of solution"=((55.38*g)/(342.3 *g*mol^-1))/(0.150*mol*L^-1)=1.079*L`