# What is the molality of a solution containing 8 moles of solute in 3.2 kg of solvnent?

$\text{Molality}$ $=$ $2.5 \cdot m o l \cdot k {g}^{-} 1$
$\text{Molality}$ is given by the quotient $\text{Moles of solute"/"kilograms of solvent}$.
And thus we simply fill in the blanks, (8*"mol")/(3.2*"kg")=2.5*"mol"*"kg"^-1.