# What is the molality of a solution in which 15 g of dissolved in 500. g of alcoholi?

$\text{Molality"="Moles of solute"/"Kilograms of solvent}$, and $\text{molality}$ is often represented by lower case $m$.
i.e. "molality"=((15*g)/("molar mass of solute(?)"))/(0.500*kg). So we need to know $\text{molar mass of solute}$ BEFORE we quote a figure in $m o l \cdot k {g}^{-} 1$.