Question

What is the molality of a solution in which 15 g of `I_2` is dissolved in 500.0 g of alcohol?

Answer 1

The molality is `=0.236mo l e s kg^-1`

Explanation:

The number of moles of iodine is `n=15/126.9=0.118 mol es`

The mass of alcohol is `=500/1000=0.5kg`

The molality is

`p=n_(solute)/m_(solvent)=0.118/0.5=0.236mo l e s kg^-1`