# What is the molality of a solution in which 15 g of I_2 is dissolved in 500.0 g of alcohol?

Dec 23, 2017

The molality is $= 0.236 m o l e s k {g}^{-} 1$

#### Explanation:

The number of moles of iodine is $n = \frac{15}{126.9} = 0.118 m o l e s$

The mass of alcohol is $= \frac{500}{1000} = 0.5 k g$

The molality is

$p = {n}_{s o l u t e} / {m}_{s o l v e n t} = \frac{0.118}{0.5} = 0.236 m o l e s k {g}^{-} 1$