Question

What is the molality of a solution prepared by dissolving 0.100 mol of chloroform, `CHCI_3`, in 400.0 g of toluene?

Answer 1

`"Molality"="Moles of solute"/"Mass of solvent (kg)"`

Explanation:

And thus..............

`"Molality"=(0.100*mol)/(0.4000*kg)=0.250*mol*kg^-1` with respect to chloroform dissolved in toluene. And of course we could express the molality with respect to toluene dissolved in chloroform.