What is the molality of a solution that contains 63.0 g HNC_3 in 0.500 kg H_2O?

May 11, 2017

What do you mean by $H N {C}_{3}$, do you mean ${H}_{2} N C {H}_{3}$, i.e. $\text{methylamine}$?

Explanation:

If you mean $\text{methylamine}$, then the molality of the solution is given by:

$\text{Moles of solute"/"Kilograms of solvent} = \frac{\frac{63.0 \cdot g}{31.06 \cdot g \cdot m o {l}^{-} 1}}{0.500 \cdot k g} = 4.06 \cdot m o l \cdot k {g}^{-} 1$.

I would not want to be downwind of such a solution. It would smell VILE! If you mean a different solute, you must specify the unambiguous chemical formula. The molarity of the solution would not be significantly different.