What is the molality of a solution when 1 mole of NaCl is dissolved in 250 ml of water?

1 Answer
anor277
May 31, 2018

#"Molality"=4.0*mol*kg^-1#

Explanation:

We want the quotient...#"molality"-="moles of solute"/"mass of solvent in kg"#

And so we got....#(1*mol)/(250*mLxx10^-3*kg*mL^-1)#

#=4.0*mol*kg^-1#

In this scenario, the #"molality"# would be only at most marginally different to the #"molarity"#. How do #"molality"# and #"molarity"# differ?

..the concentration of a saturated solution of #NaCl(aq)# is approx. #6*mol*L^-1#...

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