What is the molality when 0.15 mol SO2 is dissolved in 100 ml water? Remember 1 ml of water = 1 gram of water)

1 Answer
anor277
May 21, 2018

#"Molality"-=1.5*mol*kg^-1#...

Explanation:

By definition, #"molality"-="moles of solute"/"kilograms of solvent"#

And so here...#m_(SO_2)=(0.15*mol)/(100*mLxx1*g*mL^-1xx10^-3kg*g^-1)#

#-=1.50*mol*kg^-1#...

...sometimes this solution is referred to as #"sulfurous acid"#, i.e. #H_2SO_3-=H_2O*SO_2#...the smell is sulfurous but quite pleasant. Home brewers often use sulfurous acid to sanitize their carboys...

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