What is the molar mass of a gas if 8.482 grams of the gas will occupy 2.500 liters of space at STP?

1 Answer
Feb 10, 2016

Answer:

Approx #70-80# #g*mol^-1#.

Explanation:

At STP #1# mole of ideal gas occupies a volume of #22.41# #L#.

We assume that the unknown gas behaves ideally, so that the molar quantity is #(2.500*L)/(22.41*L*mol^-1)# #=# #0.1116# #mol#.

But this molar quantity has a mass of #8.482# #g#.

So #"Molar mass"# #=# #(8.482*g)/(0.1116*mol)# #=# #76.00# #g*mol^-1#.