Question

What is the molar volume of 3.01 x 10(23) molecules of ethane (C2H6)?

Answer 1

One mole of any gas at STP takes up 22.4 L of volume.

one mole of gas = 22.4 L ..... (a)

one mole of gas has 6.02 x `10^ 23` particles( Molecules) ..... (b)

equating (a) and (b) we get

6.022 x `10^ 23` particles (Molecules) = 22.4 L

Making conversion factors 22.4 L / 6.02 x `10^ 23` particles or

6.02 x `10^ 23` particles / 22.4 L

since we want change the # of molecules into L we will use the conversion factor that when multiplied by the given number
gives L as the final unit.

3.01 x `10^23` particles x 22.4 L / 6.02 x `10^ 23` particles

11.2 L