# What is the molar volume of 3.01 x 10(23) molecules of ethane (C2H6)?

Jun 28, 2014

One mole of any gas at STP takes up 22.4 L of volume.

one mole of gas = 22.4 L ..... (a)

one mole of gas has 6.02 x ${10}^{23}$ particles( Molecules) ..... (b)

equating (a) and (b) we get

6.022 x ${10}^{23}$ particles (Molecules) = 22.4 L

Making conversion factors 22.4 L / 6.02 x ${10}^{23}$ particles or

6.02 x ${10}^{23}$ particles / 22.4 L

since we want change the # of molecules into L we will use the conversion factor that when multiplied by the given number
gives L as the final unit.

3.01 x ${10}^{23}$ particles x 22.4 L / 6.02 x ${10}^{23}$ particles

11.2 L