# What is the molarity for 23.4 g of sodium hydroxide in 250.0 mL?

Aug 17, 2016

$\text{2.34 M}$

#### Explanation:

The molecular weight of sodium hydroxide is $\text{39.997 g/mol}$. That is, 1 mole weights $\text{39.997 g}$.

You have $\text{23.4 g}$, so you have

(23.4cancel("g"))/(39.997cancel("g")/"mol") = "0.585 moles".

These $0.585$ moles are present in $\text{250 ml}$, and $\text{250 ml}$ is equivalent to $0.25$ liters.

Molarity is moles per liter.

$\text{molarity" = "moles" / "litre}$

$\text{molarity" = "0.585 moles" / "0.25 L}$

$\text{molarity " = " 2.34 M}$

Here is a blog post on moles and molarity you might like to look at.