# What is the molarity of 2 moles of glucose in 4.00 L of a glucose solution?

May 2, 2016

Clearly, it is $0.50 \cdot m o l \cdot {L}^{-} 1$ with respect to glucose.

#### Explanation:

$\text{Concentration}$ $=$ $\text{Amount of substance in moles"/"Amount of solution in litres}$.

Given the definition, $\text{concentration}$ necessarily has units of $m o l \cdot {L}^{-} 1$.

So for your problem, we just have to set up the quotient,

$\frac{2 \cdot m o l}{4.00 \cdot L}$ =??mol*L^-1. When we set up the problem this way, it automatically gives us the correct units, $m o l \cdot {L}^{-} 1$.