# What is the molarity of 4.10 grams of magnesium chloride in 300 mL of solution?

Apr 2, 2016

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$\text{Moles of solute}$ $=$ $\frac{4.10 \cdot g}{95.21 \cdot g \cdot m o {l}^{-} 1}$ $=$ ??
$\text{Molarity}$ $=$ $\frac{\frac{4.10 \cdot g}{95.21 \cdot g \cdot m o {l}^{-} 1}}{300 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1}$ $=$ ??mol*L^-1
Given the answer what is the concentration with respect to $M {g}^{2 +}$ and $C {l}^{-}$ ions.