Question

What is the molarity of 4.10 grams of magnesium chloride in 300 mL of solution?

Answer 1

`"Molarity"` `=` `"Moles of solute"/"Volume of solution"`

Explanation:

`"Moles of solute"` `=` `(4.10*g)/(95.21*g*mol^-1)` `=` `??`

`"Molarity"` `=` `((4.10*g)/(95.21*g*mol^-1))/(300*mLxx10^-3*L*mL^-1)` `=` `??mol*L^-1`

Given the answer what is the concentration with respect to `Mg^(2+)` and `Cl^-` ions.