What is the molarity of 4.10 grams of magnesium chloride in 300 mL of solution?

1 Answer
Apr 2, 2016

Answer:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

Explanation:

#"Moles of solute"# #=# #(4.10*g)/(95.21*g*mol^-1)# #=# #??#

#"Molarity"# #=# #((4.10*g)/(95.21*g*mol^-1))/(300*mLxx10^-3*L*mL^-1)# #=# #??mol*L^-1#

Given the answer what is the concentration with respect to #Mg^(2+)# and #Cl^-# ions.