# What is the molarity of a 2.0 L sodium hydroxide solution containing 10.0 grams of solute?

Sep 11, 2017

$\text{Molarity} = 0.125 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

We take the quotient, $\frac{\frac{10.0 \cdot g}{40.00 \cdot g \cdot m o {l}^{-} 1}}{2.0 \cdot L} = 0.125 \cdot m o l \cdot {L}^{-} 1$.

Note the dimensional consistency of the answer....$\frac{1}{m o {l}^{-} 1} = \frac{1}{\frac{1}{m o l}} = m o l$.

What are the concentrations with respect to $N {a}^{+}$ and $H {O}^{-}$ ions?

What is the pH of this solution?