What is the molarity of a 2.4-liter solution containing 124 grams of HF?

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Answer 1 · 2018-05-22T05:22:46

Well, what is #"molarity"#?

By definition, #"molarity"="moles of solute"/"volume of solution"#.

And so we take the quotient...#((124*g)/(20.01*g*mol^-1))/(2.40*L)=2.58*mol*L^-1#...are the units of concentration correct?

Answer 2 · 2018-05-22T05:24:42

#"2.6 M"#

Molar mass of #"HF"# is #"20 g/mol"#

Moles of #"HF"# in solution is

#"n" = "124 g"/"20 g/mol" = "6.2 mol"#

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

#"Molarity" = "6.2 mol"/"2.4 L" = "2.6 M"#