# What is the molarity of a 2.4-liter solution containing 124 grams of HF?

May 22, 2018

Well, what is $\text{molarity}$?

#### Explanation:

By definition, $\text{molarity"="moles of solute"/"volume of solution}$.

And so we take the quotient...$\frac{\frac{124 \cdot g}{20.01 \cdot g \cdot m o {l}^{-} 1}}{2.40 \cdot L} = 2.58 \cdot m o l \cdot {L}^{-} 1$...are the units of concentration correct?

May 22, 2018

$\text{2.6 M}$

#### Explanation:

Molar mass of $\text{HF}$ is $\text{20 g/mol}$

Moles of $\text{HF}$ in solution is

$\text{n" = "124 g"/"20 g/mol" = "6.2 mol}$

$\text{Molarity" = "Moles of solute"/"Volume of solution (in litres)}$

$\text{Molarity" = "6.2 mol"/"2.4 L" = "2.6 M}$