# What is the molarity of a 250.0 milliliter aqueous solution of sodium hydroxide that contains 15.5 grams of solute?

$\left[N a O H \left(a q\right)\right] = 1.55$ $m o l \cdot {L}^{-} 1$.
$\text{Molarity}$ $=$ $\text{Moles of solute (moles)"/"Volume of solution (Litres)}$ $=$ $\frac{\frac{15.5 \cdot g}{40.0 \cdot g \cdot m o {l}^{-} 1}}{0.2500 \cdot L}$ $=$ ?? $m o l \cdot {L}^{-} 1$