# What is the molarity of a 750.0 milliliter solution containing 2.5 moles of solute?

Approx. $3.33$ $m o l \cdot {L}^{-} 1$.
$\text{Molarity}$ $=$ $\text{Amount of solute in moles"/"Volume of solution in litres}$
$=$ $\frac{2.5 \cdot m o l}{750 \times {10}^{-} 3 \cdot L}$ $=$ ?? mol*L^-1