# What is the molarity of a hydrochloric acid solution prepared by diluting 200.0 mL of 0.500 M HCl to a total volume of 1.00 L?

Sep 30, 2016

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$=$ $\frac{200 \times {10}^{-} 3 \cdot \cancel{L} \times 0.500 \cdot m o l \cdot \cancel{{L}^{-} 1}}{1.00 \cdot L}$
$=$ ??*mol*L^-1