Question

What is the molarity of a hydrochloric acid solution prepared by diluting 200.0 mL of 0.500 M HCl to a total volume of 1.00 L?

Answer 1

Clearly, the initial concentration is reduced fivefold, because you are making a fivefold dilution.

Explanation:

`"Molarity"` `=` `"Moles of solute"/"Volume of solution"`

`=` `(200xx10^-3*cancelLxx0.500*mol*cancel(L^-1))/(1.00*L)`

`=` `??*mol*L^-1`