# What is the molarity of a solution contains .250 moles of KCl in 8.00 L of solution?

$\text{Molarity"="Moles of solute"/"Volume of solution} \cong 0.03 \cdot m o l \cdot {L}^{-} 1$
And thus $\text{Molarity} = \frac{0.250 \cdot m o l}{8.00 \cdot L} \cong 0.03 \cdot m o l \cdot {L}^{-} 1$ with respect to $K C l$.