# What is the molarity of a solution in which 58 g of NaCl are dissolved in 1.0 L of solution?

A tad under $1$ $m o l \cdot {L}^{-} 1$.
Sodium chloride has an equivalent mass of $58.44 \cdot g \cdot m o {l}^{-} 1$.
Since $\text{Molarity}$ $=$ $\text{Moles of solute (mol)"/"Volume of solution (L)}$, the concentration of sodium chloride $=$ $\frac{58 \cdot g}{58.44 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{1.0 \cdot L}$ $=$ ?? $m o l \cdot {L}^{-} 1$