Question

What is the molarity of a solution made by dissolving 20.0 g of `H_3PO_4` in 50.0 mL of solution?

Answer 1

`"Molarity"` `=` `"Moles of solute"/"Volume of solution"`

Explanation:

So `"concentration"` `=` `(20.0*g)/(98.08*g*mol^-1)xx1/(50.0xx10^-3L)` `~=` `4*mol*L^-1` w.r.t. `H_3PO_4`.