# What is the molarity of a solution made by dissolving 39.4g of lithium chloride in enough water to make 1.59L of solution?

Jun 26, 2016

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$.
Here, $\text{Moles of solute"/"Volume of solution}$ $=$ $\frac{39.4 \cdot g}{42.39 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{1.59 \cdot L}$
$=$ ??*mol*L^-1