Question

What is the molarity of a solution of `KNO_3` that contains 404 grams of `KNO_3` in 2.00 liters of solution?

Answer 1

Approx. `2` `mol*L^-1`.

Explanation:

`"Concentration "= "Moles of solute"/"Volume of solution"`

We assume that potassium nitrate dissolves in the given volume of solvent without gross change in volume.

`"Concentration "=(404*cancelg)/(101.10*cancelg*mol^-1)xx(1/(2.00*L))` `=` `??mol*L^-1`.