# What is the molarity of a solution of NaOH if 2 liters of the solution contains 4 moles of NaOH?

Apr 30, 2016

$2$ $m o l \cdot {L}^{-} 1$ with respect to $N a O H$.
$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$=$ $\left(4 \cdot m o l \text{ Sodium hydroxide")/(2*L" of solution}\right)$
$=$ $2 \cdot m o l \cdot {L}^{-} 1$