What is the molarity of a solution prepared by dissolving 3.14 moles of NaOH in water and diluting to a total volume of 4.0 L?

1 Answer
anor277
May 18, 2018

#"Molarity"="moles of solute"/"volume of solution"# by definition....

Explanation:

And so we got the quotient...

#[NaOH(aq)]=(3.14*mol)/(4.0*L)#...i.e. a bit over #0.75*mol*L^-1#...and note that the quotient gave us dimensions consistent for a concentration, i.e. #mol*L^-1#...as is appropriate...

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