# What is the molarity of a solution that contains 0.00372 moles hydrochloric acid in 2.39 times 10^2 liters of solution?

May 17, 2017

1.56xx10^-5 M"

#### Explanation:

To find the molarity of this solution, we have to use the equation below:

Let's list our known and unknown values:

$\textcolor{m a \ge n t a}{\text{Knowns:}}$
- Moles of solute (0.00372 mol)
- Volume of solution (239 L)

$\textcolor{b r o w n}{\text{Unknowns:}}$
- Molarity of Solution M or $\text{mol"/"L}$

Since we know the moles of solute and volume of solution, all we have to do is divide the moles of solute by the volume of solution to obtain the molarity:

Molarity = $\text{0.00372 mol"/"239L}$

$\textcolor{red}{\text{Molarity}}$ = 1.56xx10^-5 M"