# What is the molarity of a solution that contains .250 moles of KCI in 8.00 L of solution?

May 27, 2017

$0.03125 {\text{mol dm}}^{-} 1$
$n = c V$
where $n$ is the number of moles of a solute, $c$ is the concentration or molarity of the solution and $V$ is the volume of solution.
$0.25 = 8 c$
$c = 0.03125 {\text{mol dm}}^{-} 1$