# What is the molarity of a solution that contains 3.25 moles of #"KCl"# in 2.25 L of the solution?

##### 1 Answer

#### Answer:

#### Explanation:

The idea here is that in order to find the **molarity** of the solution, you need to figure out how many moles of solute are present for every

In your case, you know that the solution contains **moles** of potassium chloride, the solute, in a total volume of

You can calculate the number of moles of potassium chloride present in **conversion factor**.

#1.00 color(red)(cancel(color(black)("L solution"))) * overbrace("3.25 moles KCl"/(2.25 color(red)(cancel(color(black)("L solution")))))^(color(blue)("the solution's composition")) = "1.44 moles KCl"#

So if **moles** of solute, you can say that the **molarity** of the solution is equal to

#color(darkgreen)(ul(color(black)("molarity = 1.44 mol L"^(-1))))#

The answer is rounded to three **sig figs**.

Notice that you can get the molarity of the solution by diving the number of moles of solute by the total volume of the solution.

This will get you

#["KCl"] = "3.25 moles"/"2.25 L" = 3.25/2.25 quad "mol"/"L" = "1.44 mol L"^(-1)#