# What is the molarity of a solution that contains 3.25 moles of NaNO_3 in 250 mL of solution?

Apr 25, 2016

$> \text{10 moles per litre}$

#### Explanation:

$\text{Molarity" = "Moles of solute (moles)"/"Volume of solution (L)}$.

For your problem, $\frac{\text{3.25 moles sodium nitrate}}{250 \times {10}^{-} 3 \cdot L}$

$=$ ??*mol*L^-1

The general aqueous solubility of nitrate species allows such a high concentration to be achieved.