# What is the molarity of a solution that contains 50 grams of NaOH dissolved in 250 ml solution?

$\text{Molarity}$ $= \text{Moles of solute"/"Volume of solution} = 5.0 \cdot m o l \cdot {L}^{-} 1$
And thus $\text{Molarity} = \frac{\frac{50 \cdot g}{40.0 \cdot g \cdot m o {l}^{-} 1}}{250 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1}$
So $\left[N a O H \left(a q\right)\right] = 5.0 \cdot m o l \cdot {L}^{-} 1$.