# What is the molarity of a solution that contains 9.63 grams of HCI in 1.5 liters of solution?

May 28, 2017

$\text{Molarity} = 0.264 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

$\text{Molarity"="Moles of solute"/"Volume of solution}$

And thus $\text{Molarity} = \frac{\frac{9.63 \cdot g}{36.46 \cdot g \cdot m o {l}^{-} 1}}{1.5 \cdot L} = 0.264 \cdot m o l \cdot {L}^{-} 1.$

Note that our dimensions our consistent. We wanted an answer with units of concentrations, i.e. $m o l \cdot {L}^{-} 1$, and the given quotient gave us an answer with such units. It is all too easy to multiply when you should divide, and vice versa.

What is $p H$ of this solution?