# What is the molarity of a solution that has .93 moles of NaOH in 1.5 liters of solution?

Apr 22, 2016

The molarity of the solution is $\text{0.62 mol/L}$.

#### Explanation:

The equation relating moles and volume is $\text{M"="n"/"V}$, where $\text{M}$ is molarity, $\text{n}$ is moles, and $\text{V}$ is volume in liters.

Given values are $\text{0.93 mol NaOH}$, and $\text{1.5 L solution}$.

Substitute the given values into the equation.

$\text{M"=(0.93"mol NaOH")/(1.5"L solution")="0.62 mol/L}$