# What is the molarity of a solution with 16 g of CH_3OH in 7 mL of solution?

molar mass of $C {H}_{3} O H = 12 + 4 + 15 = 32 \frac{g}{m o l}$
Amount of $C {H}_{3} O H = 16 g = 16 g \times \frac{1}{32} \times \frac{m o l}{g} = 0.5 m o l$
So molarity =$0.5 \times \frac{1000}{7} = 71.4 m$