# What is the molarity of a solution with 6 g of NaOH in enough water to make a 2 L solution?

##### 1 Answer
May 26, 2016

$\text{Molarity}$ $=$ $\text{Moles of solute (moles)"/"Volume of solution (L) }$

Here, approx. $0.05 \cdot m o l \cdot {L}^{-} 1$.

#### Explanation:

And thus,

$\text{Concentration (NaOH)}$ $=$ $\frac{6 \cdot g}{58.44 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{2 \cdot L}$ $=$ ??mol*L^-1.