Question

What is the molarity of a solution with 73 g of `HCl` in 319 mL of solution?

Answer 1

Approx. `6.5*mol*L^-1` with respect to hydrochloric acid.

Explanation:

`"Molarity"` `=` `"Moles of solute"/"Volume of solution"`

`=` `(73*g)/(35.45*g*mol^-1)xx1/(0.319*L)` `=` `??*mol*L^-1`.